# Percentage MCQ Test 2

### 1. Balanced diet should contain 12% of proteins, 25% of fats and 63% of carbohydrates. If a child needs 2600 calories in this food daily, find in calories the amount of carbohydrates in his daily food intake.

a balanced diet contains 63% carbohydrates.
∴ Amount of carbohydrates in food intake = 63% of 2600=63100×2600=1638

### 2. A cricketer scored a total of 62 runs in 96 balls. He hit 3 sixes, 8 fours, 2 twos and 8 singles. What percentage of the total runs came in singles?

The cricketer hits 8 singles.i.e., 8×1=8∴ 862×100=12.90%

### 3. 72% of 25 students are good in Mathematics. How many are not good in Mathematics?

Explanation/Answer:- (100-72)% =28% Not good in mathemetics.
∴ 28% of 25=28/100*25=7

### 4. If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?

Explanation/Answer:- 40% of x = 2/3 of y => 2/5*x= 2/3*y=>5/3

### 5. Two fifth of one third of three seventh of a number is 15. What is 40 percent of that number?

40% of X =40/100*(15*5*3*7)/(2*3)=105

### 6. If A is 25% of B then what % is B of A?

Explanation/Answer:- LET B IS 100 SO A=25
% is B of A=100/25*10=400

### 7. Let x and y be two numbers such that x = 5y. Then y is less than x by:

Y is less than x by=x-y/x*100 => (1-y/x)*100 => (1-1/5)*100 => 4/5*100=80%

### 8. The numerator of a fraction is increased by 20% and its denominator be diminished by 10%. The value of new fraction is , then the fraction is:

Explanation/Answer:- (100+20)/(100-10) = 120/90 = 4/3

### 9. The price of sugar rises by 50%. By what percent family reduces the consumption of sugar, so that the expenditure does not increase?

Explanation/Answer:- Let the Initial price of sugar = 100 per kg
Now the price of sugar = 150 per kg
Initially family was conusming 100 Rs. for 1 kg of sugar.
Sugar quantity with new rate 150 Rs. per kg for 100 Rs. = 100/150 = 2/5 kg (0.4 kg)
Percentage of consumption should reduce by = (1-0.4)/100
= 0.6/100
= 60%